Displaying files and increment them +1
I'm creating a script that lists all the nano files in a directory. han than the files are added with a number. (Adding +1 for every file). Then the user is allowed to view the nano file.
Here is what I have so far. I want to point out that all the filenames end with _log
so that's why I'm hoping that the grep works like this.
path=~/home/folder/list
list=$(`ls $path | grep -i *_log`)
printf '%sn' "${list[@]}" | nl -v 1
read -p "Number of file to be displayed:" numb
sudo cat $path/${list [numb]}
bash shell-script
New contributor
add a comment |
I'm creating a script that lists all the nano files in a directory. han than the files are added with a number. (Adding +1 for every file). Then the user is allowed to view the nano file.
Here is what I have so far. I want to point out that all the filenames end with _log
so that's why I'm hoping that the grep works like this.
path=~/home/folder/list
list=$(`ls $path | grep -i *_log`)
printf '%sn' "${list[@]}" | nl -v 1
read -p "Number of file to be displayed:" numb
sudo cat $path/${list [numb]}
bash shell-script
New contributor
add a comment |
I'm creating a script that lists all the nano files in a directory. han than the files are added with a number. (Adding +1 for every file). Then the user is allowed to view the nano file.
Here is what I have so far. I want to point out that all the filenames end with _log
so that's why I'm hoping that the grep works like this.
path=~/home/folder/list
list=$(`ls $path | grep -i *_log`)
printf '%sn' "${list[@]}" | nl -v 1
read -p "Number of file to be displayed:" numb
sudo cat $path/${list [numb]}
bash shell-script
New contributor
I'm creating a script that lists all the nano files in a directory. han than the files are added with a number. (Adding +1 for every file). Then the user is allowed to view the nano file.
Here is what I have so far. I want to point out that all the filenames end with _log
so that's why I'm hoping that the grep works like this.
path=~/home/folder/list
list=$(`ls $path | grep -i *_log`)
printf '%sn' "${list[@]}" | nl -v 1
read -p "Number of file to be displayed:" numb
sudo cat $path/${list [numb]}
bash shell-script
bash shell-script
New contributor
New contributor
edited 46 mins ago
terdon♦
128k31249423
128k31249423
New contributor
asked 1 hour ago
User101
133
133
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New contributor
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add a comment |
1 Answer
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If I understand correctly, you want to make an array holding all the files and then display the contents of whichever file corresponds to the number entered by the user. If so, you are making things far more complicated than necessary. This should be enough:
## Get the files into the array $list
list=(/home/folder/list/*_log)
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]}";
done
## Get the user input
read -p "Number of file to be displayed:" numb
## display the file (don't use sudo unless absolutely necessary)
cat "${list[numb]}"
Note that this will display the file names including the entire path. To display the names only, change the for
loop to:
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]##*/}"
done
Still the files aren't displayed however when i type a number i can view the file as I should be. Can't figure out why it won't display all the files though.
– User101
5 mins ago
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
If I understand correctly, you want to make an array holding all the files and then display the contents of whichever file corresponds to the number entered by the user. If so, you are making things far more complicated than necessary. This should be enough:
## Get the files into the array $list
list=(/home/folder/list/*_log)
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]}";
done
## Get the user input
read -p "Number of file to be displayed:" numb
## display the file (don't use sudo unless absolutely necessary)
cat "${list[numb]}"
Note that this will display the file names including the entire path. To display the names only, change the for
loop to:
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]##*/}"
done
Still the files aren't displayed however when i type a number i can view the file as I should be. Can't figure out why it won't display all the files though.
– User101
5 mins ago
add a comment |
If I understand correctly, you want to make an array holding all the files and then display the contents of whichever file corresponds to the number entered by the user. If so, you are making things far more complicated than necessary. This should be enough:
## Get the files into the array $list
list=(/home/folder/list/*_log)
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]}";
done
## Get the user input
read -p "Number of file to be displayed:" numb
## display the file (don't use sudo unless absolutely necessary)
cat "${list[numb]}"
Note that this will display the file names including the entire path. To display the names only, change the for
loop to:
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]##*/}"
done
Still the files aren't displayed however when i type a number i can view the file as I should be. Can't figure out why it won't display all the files though.
– User101
5 mins ago
add a comment |
If I understand correctly, you want to make an array holding all the files and then display the contents of whichever file corresponds to the number entered by the user. If so, you are making things far more complicated than necessary. This should be enough:
## Get the files into the array $list
list=(/home/folder/list/*_log)
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]}";
done
## Get the user input
read -p "Number of file to be displayed:" numb
## display the file (don't use sudo unless absolutely necessary)
cat "${list[numb]}"
Note that this will display the file names including the entire path. To display the names only, change the for
loop to:
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]##*/}"
done
If I understand correctly, you want to make an array holding all the files and then display the contents of whichever file corresponds to the number entered by the user. If so, you are making things far more complicated than necessary. This should be enough:
## Get the files into the array $list
list=(/home/folder/list/*_log)
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]}";
done
## Get the user input
read -p "Number of file to be displayed:" numb
## display the file (don't use sudo unless absolutely necessary)
cat "${list[numb]}"
Note that this will display the file names including the entire path. To display the names only, change the for
loop to:
## Display the file names
for i in ${!list[@]}; do
printf "%s: %sn" $i "${list[i]##*/}"
done
answered 34 mins ago
terdon♦
128k31249423
128k31249423
Still the files aren't displayed however when i type a number i can view the file as I should be. Can't figure out why it won't display all the files though.
– User101
5 mins ago
add a comment |
Still the files aren't displayed however when i type a number i can view the file as I should be. Can't figure out why it won't display all the files though.
– User101
5 mins ago
Still the files aren't displayed however when i type a number i can view the file as I should be. Can't figure out why it won't display all the files though.
– User101
5 mins ago
Still the files aren't displayed however when i type a number i can view the file as I should be. Can't figure out why it won't display all the files though.
– User101
5 mins ago
add a comment |
User101 is a new contributor. Be nice, and check out our Code of Conduct.
User101 is a new contributor. Be nice, and check out our Code of Conduct.
User101 is a new contributor. Be nice, and check out our Code of Conduct.
User101 is a new contributor. Be nice, and check out our Code of Conduct.
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