Why doesn't using two cd commands in bash script execute the second command?
I have written a bash script which creates a series of directories and clones a project to selected directories.
For that, I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory nor executes the command.
Instead, it stops after cd
and cloning in theproject2
directory. Why doesn't it call the cd_project1
function in the following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
New contributor
|
show 9 more comments
I have written a bash script which creates a series of directories and clones a project to selected directories.
For that, I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory nor executes the command.
Instead, it stops after cd
and cloning in theproject2
directory. Why doesn't it call the cd_project1
function in the following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
New contributor
2
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
yesterday
1
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
yesterday
2
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
yesterday
2
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
yesterday
5
I'm curious what you intended for theexec bash
to do.
– Dennis Williamson
yesterday
|
show 9 more comments
I have written a bash script which creates a series of directories and clones a project to selected directories.
For that, I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory nor executes the command.
Instead, it stops after cd
and cloning in theproject2
directory. Why doesn't it call the cd_project1
function in the following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
New contributor
I have written a bash script which creates a series of directories and clones a project to selected directories.
For that, I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory nor executes the command.
Instead, it stops after cd
and cloning in theproject2
directory. Why doesn't it call the cd_project1
function in the following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
bash scripts cd-command
New contributor
New contributor
edited 16 hours ago
Dan
7,13034573
7,13034573
New contributor
asked yesterday
JennyJenny
665
665
New contributor
New contributor
2
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
yesterday
1
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
yesterday
2
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
yesterday
2
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
yesterday
5
I'm curious what you intended for theexec bash
to do.
– Dennis Williamson
yesterday
|
show 9 more comments
2
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
yesterday
1
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
yesterday
2
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
yesterday
2
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
yesterday
5
I'm curious what you intended for theexec bash
to do.
– Dennis Williamson
yesterday
2
2
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
yesterday
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
yesterday
1
1
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
yesterday
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
yesterday
2
2
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
yesterday
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
yesterday
2
2
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
yesterday
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
yesterday
5
5
I'm curious what you intended for the
exec bash
to do.– Dennis Williamson
yesterday
I'm curious what you intended for the
exec bash
to do.– Dennis Williamson
yesterday
|
show 9 more comments
3 Answers
3
active
oldest
votes
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
1
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
yesterday
6
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
yesterday
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
add a comment |
if you want a return to the directory you started you could use
cd -
But if you are not sure whether a cd
command was executed at all it would be better to use the commands for putting working directories onto a stack:
pushd
and return to it (even after multiple directory changes)
popd
be sure to have equaly pushd
and popd
commands.
1
I'm not sure you read or understood the problem space. None of these commands will help the user.
– pipe
17 hours ago
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "89"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f1125755%2fwhy-doesnt-using-two-cd-commands-in-bash-script-execute-the-second-command%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
1
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
yesterday
6
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
yesterday
add a comment |
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
1
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
yesterday
6
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
yesterday
add a comment |
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
answered yesterday
PerlDuckPerlDuck
7,19611636
7,19611636
1
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
yesterday
6
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
yesterday
add a comment |
1
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
yesterday
6
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
yesterday
1
1
@Jenny Nice to hear. Anecdote: The Perl language also has an
exec
statement with the same behaviour and if you put some statements after an exec
statement (like exec something; print "This won't run";
) then Perl will warn you that the print
statement will never get executed.– PerlDuck
yesterday
@Jenny Nice to hear. Anecdote: The Perl language also has an
exec
statement with the same behaviour and if you put some statements after an exec
statement (like exec something; print "This won't run";
) then Perl will warn you that the print
statement will never get executed.– PerlDuck
yesterday
6
6
BTW congrats on using && after cd, (if you don’t use
set -e
). I have seen Code like cd tmp; rm -rf *
fail horrible– eckes
yesterday
BTW congrats on using && after cd, (if you don’t use
set -e
). I have seen Code like cd tmp; rm -rf *
fail horrible– eckes
yesterday
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
answered yesterday
steeldriversteeldriver
69.4k11114186
69.4k11114186
add a comment |
add a comment |
if you want a return to the directory you started you could use
cd -
But if you are not sure whether a cd
command was executed at all it would be better to use the commands for putting working directories onto a stack:
pushd
and return to it (even after multiple directory changes)
popd
be sure to have equaly pushd
and popd
commands.
1
I'm not sure you read or understood the problem space. None of these commands will help the user.
– pipe
17 hours ago
add a comment |
if you want a return to the directory you started you could use
cd -
But if you are not sure whether a cd
command was executed at all it would be better to use the commands for putting working directories onto a stack:
pushd
and return to it (even after multiple directory changes)
popd
be sure to have equaly pushd
and popd
commands.
1
I'm not sure you read or understood the problem space. None of these commands will help the user.
– pipe
17 hours ago
add a comment |
if you want a return to the directory you started you could use
cd -
But if you are not sure whether a cd
command was executed at all it would be better to use the commands for putting working directories onto a stack:
pushd
and return to it (even after multiple directory changes)
popd
be sure to have equaly pushd
and popd
commands.
if you want a return to the directory you started you could use
cd -
But if you are not sure whether a cd
command was executed at all it would be better to use the commands for putting working directories onto a stack:
pushd
and return to it (even after multiple directory changes)
popd
be sure to have equaly pushd
and popd
commands.
answered 22 hours ago
Bernd Wilke πφBernd Wilke πφ
1265
1265
1
I'm not sure you read or understood the problem space. None of these commands will help the user.
– pipe
17 hours ago
add a comment |
1
I'm not sure you read or understood the problem space. None of these commands will help the user.
– pipe
17 hours ago
1
1
I'm not sure you read or understood the problem space. None of these commands will help the user.
– pipe
17 hours ago
I'm not sure you read or understood the problem space. None of these commands will help the user.
– pipe
17 hours ago
add a comment |
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Ask Ubuntu!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f1125755%2fwhy-doesnt-using-two-cd-commands-in-bash-script-execute-the-second-command%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
yesterday
1
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
yesterday
2
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
yesterday
2
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
yesterday
5
I'm curious what you intended for the
exec bash
to do.– Dennis Williamson
yesterday