RegionDifference for Cylinder and Cuboid












5












$begingroup$


I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try



reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.










share|improve this question









$endgroup$








  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    yesterday








  • 2




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    yesterday
















5












$begingroup$


I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try



reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.










share|improve this question









$endgroup$








  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    yesterday








  • 2




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    yesterday














5












5








5





$begingroup$


I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try



reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.










share|improve this question









$endgroup$




I wish to use RegionDifference to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]


Mathematica graphics



So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try



reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]


Mathematica graphics



My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?



Version 11.3 for windows.







regions






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked yesterday









HughHugh

6,50421945




6,50421945








  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    yesterday








  • 2




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    yesterday














  • 1




    $begingroup$
    Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
    $endgroup$
    – Henrik Schumacher
    yesterday








  • 2




    $begingroup$
    I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
    $endgroup$
    – Hugh
    yesterday








1




1




$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
$endgroup$
– Henrik Schumacher
yesterday






$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the BooleanRegion facilities.
$endgroup$
– Henrik Schumacher
yesterday






2




2




$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday




$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday










2 Answers
2






active

oldest

votes


















6












$begingroup$

Please note the RegionBounds:



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];

bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]


enter image description here






share|improve this answer









$endgroup$













  • $begingroup$
    Whoa. Why did PlotRange -> All not work? Anyways, good job!
    $endgroup$
    – Henrik Schumacher
    yesterday










  • $begingroup$
    I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
    $endgroup$
    – Hugh
    yesterday










  • $begingroup$
    @Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
    $endgroup$
    – rmw
    18 hours ago



















3












$begingroup$

This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]


enter image description here



As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






share|improve this answer











$endgroup$













  • $begingroup$
    @JasonB. Thank you for the edit. That was an error that I make too often...
    $endgroup$
    – Henrik Schumacher
    yesterday











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









6












$begingroup$

Please note the RegionBounds:



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];

bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]


enter image description here






share|improve this answer









$endgroup$













  • $begingroup$
    Whoa. Why did PlotRange -> All not work? Anyways, good job!
    $endgroup$
    – Henrik Schumacher
    yesterday










  • $begingroup$
    I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
    $endgroup$
    – Hugh
    yesterday










  • $begingroup$
    @Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
    $endgroup$
    – rmw
    18 hours ago
















6












$begingroup$

Please note the RegionBounds:



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];

bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]


enter image description here






share|improve this answer









$endgroup$













  • $begingroup$
    Whoa. Why did PlotRange -> All not work? Anyways, good job!
    $endgroup$
    – Henrik Schumacher
    yesterday










  • $begingroup$
    I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
    $endgroup$
    – Hugh
    yesterday










  • $begingroup$
    @Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
    $endgroup$
    – rmw
    18 hours ago














6












6








6





$begingroup$

Please note the RegionBounds:



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];

bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]


enter image description here






share|improve this answer









$endgroup$



Please note the RegionBounds:



reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];

bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered yesterday









rmwrmw

3497




3497












  • $begingroup$
    Whoa. Why did PlotRange -> All not work? Anyways, good job!
    $endgroup$
    – Henrik Schumacher
    yesterday










  • $begingroup$
    I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
    $endgroup$
    – Hugh
    yesterday










  • $begingroup$
    @Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
    $endgroup$
    – rmw
    18 hours ago


















  • $begingroup$
    Whoa. Why did PlotRange -> All not work? Anyways, good job!
    $endgroup$
    – Henrik Schumacher
    yesterday










  • $begingroup$
    I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
    $endgroup$
    – Hugh
    yesterday










  • $begingroup$
    @Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
    $endgroup$
    – rmw
    18 hours ago
















$begingroup$
Whoa. Why did PlotRange -> All not work? Anyways, good job!
$endgroup$
– Henrik Schumacher
yesterday




$begingroup$
Whoa. Why did PlotRange -> All not work? Anyways, good job!
$endgroup$
– Henrik Schumacher
yesterday












$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday




$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday












$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago




$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago











3












$begingroup$

This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]


enter image description here



As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






share|improve this answer











$endgroup$













  • $begingroup$
    @JasonB. Thank you for the edit. That was an error that I make too often...
    $endgroup$
    – Henrik Schumacher
    yesterday
















3












$begingroup$

This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]


enter image description here



As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






share|improve this answer











$endgroup$













  • $begingroup$
    @JasonB. Thank you for the edit. That was an error that I make too often...
    $endgroup$
    – Henrik Schumacher
    yesterday














3












3








3





$begingroup$

This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]


enter image description here



As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.






share|improve this answer











$endgroup$



This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.



reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]


enter image description here



As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion nor a BoundaryMeshRegion.







share|improve this answer














share|improve this answer



share|improve this answer








edited yesterday









Jason B.

48.6k388196




48.6k388196










answered yesterday









Henrik SchumacherHenrik Schumacher

56.6k577157




56.6k577157












  • $begingroup$
    @JasonB. Thank you for the edit. That was an error that I make too often...
    $endgroup$
    – Henrik Schumacher
    yesterday


















  • $begingroup$
    @JasonB. Thank you for the edit. That was an error that I make too often...
    $endgroup$
    – Henrik Schumacher
    yesterday
















$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday




$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday


















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