RegionDifference for Cylinder and Cuboid
$begingroup$
I wish to use RegionDifference
to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]
So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try
reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]
My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?
Version 11.3 for windows.
regions
$endgroup$
add a comment |
$begingroup$
I wish to use RegionDifference
to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]
So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try
reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]
My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?
Version 11.3 for windows.
regions
$endgroup$
1
$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of theBooleanRegion
facilities.
$endgroup$
– Henrik Schumacher
yesterday
2
$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday
add a comment |
$begingroup$
I wish to use RegionDifference
to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]
So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try
reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]
My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?
Version 11.3 for windows.
regions
$endgroup$
I wish to use RegionDifference
to take a cube shape out of a cylinder. First I make the cylinder and cube and combine them in RegionUnion.
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
Region[RegionUnion[reg1, reg2], Axes -> True]
So this looks good so far. Now I wish to take the cuboid out of the cylinder leaving a notch in the cylinder. I try
reg = RegionDifference[reg1, reg2];
Region[reg, Axes -> True, PlotRange -> All]
My cylinder is chopped off short and given a bad end (away from the subtraction). Is there a workaround?
Version 11.3 for windows.
regions
regions
asked yesterday
HughHugh
6,50421945
6,50421945
1
$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of theBooleanRegion
facilities.
$endgroup$
– Henrik Schumacher
yesterday
2
$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday
add a comment |
1
$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of theBooleanRegion
facilities.
$endgroup$
– Henrik Schumacher
yesterday
2
$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday
1
1
$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the
BooleanRegion
facilities.$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the
BooleanRegion
facilities.$endgroup$
– Henrik Schumacher
yesterday
2
2
$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday
$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Please note the RegionBounds
:
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];
bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]
$endgroup$
$begingroup$
Whoa. Why didPlotRange -> All
not work? Anyways, good job!
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday
$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago
add a comment |
$begingroup$
This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.
reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]
As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion
nor a BoundaryMeshRegion
.
$endgroup$
$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Please note the RegionBounds
:
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];
bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]
$endgroup$
$begingroup$
Whoa. Why didPlotRange -> All
not work? Anyways, good job!
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday
$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago
add a comment |
$begingroup$
Please note the RegionBounds
:
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];
bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]
$endgroup$
$begingroup$
Whoa. Why didPlotRange -> All
not work? Anyways, good job!
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday
$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago
add a comment |
$begingroup$
Please note the RegionBounds
:
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];
bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]
$endgroup$
Please note the RegionBounds
:
reg1 = Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5];
reg2 = Cuboid[{5, 0, 0}, {10, 1, 1}];
reg = RegionDifference[reg1, reg2];
bounds = RegionBounds@reg;
Region[reg, Axes -> True, PlotRange -> bounds]
answered yesterday
rmwrmw
3497
3497
$begingroup$
Whoa. Why didPlotRange -> All
not work? Anyways, good job!
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday
$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago
add a comment |
$begingroup$
Whoa. Why didPlotRange -> All
not work? Anyways, good job!
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday
$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago
$begingroup$
Whoa. Why did
PlotRange -> All
not work? Anyways, good job!$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
Whoa. Why did
PlotRange -> All
not work? Anyways, good job!$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday
$begingroup$
I put in PlotRange All because I wondered if it was a plotting problem. Are there known issues with PlotRange?
$endgroup$
– Hugh
yesterday
$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago
$begingroup$
@Hugh How Mathematica works is probably only known to the developers. For the user remains only trial and error. But I have already encountered this problem earlier. You have sent it off to support, that's ok.
$endgroup$
– rmw
18 hours ago
add a comment |
$begingroup$
This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.
reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]
As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion
nor a BoundaryMeshRegion
.
$endgroup$
$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.
reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]
As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion
nor a BoundaryMeshRegion
.
$endgroup$
$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.
reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]
As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion
nor a BoundaryMeshRegion
.
$endgroup$
This seems to be a viable workaround although it is a shame that we have to discretize the cylinder that early.
reg1 = BoundaryDiscretizeRegion[Cylinder[{{0, 0, 0}, {10, 0, 0}}, 0.5], MaxCellMeasure -> 0.001];
reg2 = BoundaryDiscretizeRegion[Cuboid[{5, 0, 0}, {10, 1, 1}]];
reg = RegionDifference[reg1, reg2]
As a rule of thumb, I would strongly discourage applying boolean operations to graphics primitives and everything else which is neither a MeshRegion
nor a BoundaryMeshRegion
.
edited yesterday
Jason B.
48.6k388196
48.6k388196
answered yesterday
Henrik SchumacherHenrik Schumacher
56.6k577157
56.6k577157
$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
@JasonB. Thank you for the edit. That was an error that I make too often...
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
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1
$begingroup$
Wow, that's really weird. Please contact support. Honestly, I am quite disappointed with the almost nonexistent usability of the
BooleanRegion
facilities.$endgroup$
– Henrik Schumacher
yesterday
2
$begingroup$
I have sent it off to support.I agree about being fed up. Second time in two days you have had to help me out -for which I am very grateful.
$endgroup$
– Hugh
yesterday